c++ Double precision decimal places

In C++ there are two ways to represent/store decimal values. You may need to adjust your routine to work on chars, which usually don’t range up to 4096, and there may also be some weirdness with endianness here, but the basic idea should work. It won’t be cross-platform compatible, since machines use different endianness and representations of doubles, so be careful how you use this. The commented out ‘image_print()` function prints an arbitrary set of bytes in hex, with various minor tweaks.

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The IEEE single precision floating point standard representation requires a 32 bit word, which may be represented as numbered from 0 to 31, left to right. There’s no exact conversion from a given number of bits to a given number of decimal digits. 3 bits can hold values from 0 to 7, and 4 bits can hold values from 0 to 15. A value from 0 to 9 takes roughly 3.5 bits, but that’s not exact either.

Note that this is one place that printf format strings differ substantially from scanf (and fscanf, etc.) format strings. For output, you’re passing a value, which will be promoted from float to double when passed as a variadic parameter. Basically single precision floating point arithmetic deals with 32 bit floating point numbers whereas double precision deals with 64 bit. The precision indicates the number of decimal digits that are correct, i.e. without any kind of representation error or approximation.

If we assume the IEEE standard, then a single precision number has about 23 bits of the mantissa, and a maximum exponent of about 38; a double precision has 52 bits for the mantissa, and a maximum exponent of about 308. The IEEE double precision floating point standard representation requires a 64 bit word, which may be represented as numbered from 0 to 63, left to right. As to the question « Can the ps3 and xbxo 360 pull off double precision floating point operations or only single precision and in generel use is the double precision capabilities made use of (if they exist?). » The number of bits in double precision increases the maximum value that can be stored as well as increasing the precision (ie the number of significant digits).

A double can store values from:

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The last decimal digit (16th or 17th) is not necessarily accurate after math operations (at least not in all implementations and platforms); hence, limit your code to 15 digits. So, because there is no sane or useful interpretation of the bit operators to double values, they are not allowed by double entry system of accounting the standard. I believe that both platforms are incapable of double floating point.

L Specifies that a following a, A, e, E, f, F, g, or G conversion specifier applies to a long double argument. If you want finite values, then you can use max, which will be greater than or equal to all other finite values, and lowest, which is less then or equal to all other finite values. If has_infinity is true (which it will for basically any platform nowadays), then you can use infinity to get the value which is greater than or equal to all other values (except NaNs). Its negation will give a negative infinity, and be less than or equal to all other values (except NaNs again).

What are the actual min/max values for float and double (C++)

First of all float and double are both used for representation of numbers fractional numbers. So, the difference between the two stems from the fact with how much precision they can store the numbers. Okay, the basic difference at the machine is that double precision uses twice as many bits as single.

How do I use bitwise operators on a « double » on C++?

« %lf » is also acceptable under the current standard — the l is specified as having no effect if followed by the f conversion specifier (among others). Now by accessing elements c0 through csizeof(double) – 1 you will see the internal representation of type double. You can use bitwise operations on these unsigned char values, if you want to. Bitwise operators don’t generally work with « binary representation » (also called object representation) of any type. Bitwise operators work with value representation of the type, which is generally different from object representation.

For example, does the Nintendo 64 have a 64 bit processor and if it does then would that mean it was capable of double precision floating point operations? Can the PS3 and Xbox 360 pull off double precision floating point operations or only single precision and in general use is the double precision capabilities made use of (if they exist?). If the double reaches its positive max or min, or its negative max or min, many languages will always return one of those values in some form. But often these four values are your TRUE min and max values for double. By returning irrational values, you at least have have a representation of the max and min in doubles that explain the last forms of the double type that cannot be stored or explained rationally. Doubles always have 53 significant bits and floats always have 24 significant bits (except for denormals, infinities, and NaN values, but those are subjects for a different question).

Double precision – decimal places

The original Cell processor only had 32 bit floats, same with the ATI hardware which the XBox 360 is based on (R600). The Cell got double floating point support later on, but I’m pretty sure the PS3 doesn’t use that chippery. I read a lot of answers but none seems to correctly explain where the word double comes from. I remember a very good explanation given by a University professor I had some years ago. So you can see with +-Infinity and +-0 added, Doubles have extra max and min ranges to help you when you exceed the max and mins.

A double can store values from:

  • Doubles always have 53 significant bits and floats always have 24 significant bits (except for denormals, infinities, and NaN values, but those are subjects for a different question).
  • As others has noted, I will assume that the OP asked for the largest floating-point value such that all whole numbers less than itself is precisely representable.
  • It won’t be cross-platform compatible, since machines use different endianness and representations of doubles, so be careful how you use this.
  • In the usual implementation,that’s 32 bits for single, 64 bits for double.
  • What is the correct format specifier for double in printf?

Format %lf in printf was not supported in old (pre-C99) versions of C language, which created superficial « inconsistency » between format specifiers for double in printf and scanf. It can be %f, %g or %e depending on how you want the number to be formatted. The l modifier is required in scanf with double, but not in printf.

  • The reason it’s called a double is because the number of bytes used to store it is double the number of a float (but this includes both the exponent and significand).
  • There’s no exact conversion from a given number of bits to a given number of decimal digits.
  • Suppose for a moment that you could shift a double right.
  • If has_infinity is true (which it will for basically any platform nowadays), then you can use infinity to get the value which is greater than or equal to all other values (except NaNs).
  • Its negation will give a negative infinity, and be less than or equal to all other values (except NaNs again).

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In the usual implementation,that’s 32 bits for single, 64 bits for double. But since the fraction is a binary number, α1 will always be equal to 1, thus the fraction can be rewritten as 1.α2α3…αt+1 × 2p and the initial 1 can be implicitly assumed, making room for an extra bit (αt+1). The encoding of a double uses 64 bits (1 bit for the sign, 11 bits for the exponent, 52 explicit significant bits and one implicit bit), which is double the number of bits used to represent a float (32 bits). As mentioned earlier, computers cannot represent real numbers precisely since there are only a finite number of bits for storing a real number. Therefore, any number that has infinite number of digits such as 1/3, the square root of 2 and PI cannot be represented completely. Moreover, even a number of finite number of digits cannot be represented precisely because of the way of encoding real numbers.

JavaScript (which also uses the 64-bit double precision storage system for numbers in computers) uses double precision floating point numbers for storing all known numerical values. But most languages use a typed numerical system with ranges to avoid accuracy problems. The double and float number storage systems, however, seem to all share the same flaw of losing numerical precision as they get larger and smaller. I will explain why as it affects the idea of « maximum » values…

The code below shows an overloaded method, which I assume is similar to your lab code. If you’re using Intel (little-endian), you’ll probably need to tweak the code to deal with the reverse bit order. Similar comments apply to any of the other bit operators. The program fails when I try to instantiate the template using a « double » or a « float ». Notice how I changed the last digit, but it printed out the same number anyway.

The N64 used a MIPS R4300i-based NEC VR4300 which is a 64 bit processor, but the processor communicates with the rest of the system over a 32-bit wide bus. So, most developers used 32 bit numbers because they are faster, and most games at the time did not need the additional precision (so they used floats not doubles). The IEEE double-precision format actually has more than twice as many bits of precision as the single-precision format, as well as a much greater range. Notice that the 2 to power of 1023 translates to a decimal exponent using 10 to the power of 308 for max values. That allows you to see the number in Human values, or Base10 numerical format of the binary calculation. Often math experts do not explain that all these values are the same number just in different bases or formats.

In general, you need over 100 decimal places to do that precisely. You can use %f as well, if you so prefer (%lf and %f are equivalent in printf). But in modern C it makes perfect sense to prefer to use %f with float, %lf with double and %Lf with long double, consistently in both printf and scanf. Format %lf is a perfectly correct printf format for double, exactly as you used it.

Thus, this exponent number allows for a full range of large and small decimals to be created with the floating radix or decimal point to move up and down the number, creating the complex fractional or decimal values you expect to see. Again, this exponent is another large number store in 11-bits, and itself has a max value of 2048. I’m especially interested in practical terms in relation to video game consoles.

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